How to calculate maximum height due to drop on a lever? - correct height to sit at computer
When a ball is dropped from a height on a swing (which I do for a 1st-class lever with a pivotal point in the middle, right?) And there's a second ball of the same mass SIT - for the the other end of the arm, how to calculate the amount, when the second ball goes? Aside from friction, the second ball to be achieved at the same level as the first ball to be dropped from?
To be clear: the first ball is not really on the lever when it bends. The height above the raised arm of the lever, and no connection to him, until he at some distance from the force of gravity.
Energy of this movement. Use GPE = mgh for potential energy of the first ball at the start to be calculated, so that everything is converted into kinetic energy just before reaching the switch - 1/2mv MGH = ^ 2 Everything is transmitted to the second ball, and assuming a low friction. With kinetic energy = 1/2mv ^ 2 for the second new ball. Assumption that no air resistance, but it will not transfer grav. potential energy in the way up. and the use of 1/2mv ^ 2 = mgh, h can be calculated if the masses of the two spheres.
ReplyDeleteIs a simple way to solve this problem, but I'm sure it works:)